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A. 288 g sample of an unknown monoprotic organic acid is dissolved in water and titrated with a. 115 m sodium hydroxide solution. After the addition of 17. 54 ml of base, a ph of 4. 92 is recorded. The equivalence point is reached. Ka is an acronym that stand for acid dissociation constant.
Assuming hc is an acid, as given in the question a monoprotic acid. Then, the dissociation is given below as: Enough of a monoprotic acid is dissolved in water to produce a 1. 261. 26 m solution. The ph of the resulting solution is 2. 702. 70. Calculate the k a for the acid. Enough of a monoprotic acid is dissolved in water to produce a 0. 0192 m solution. The ph of the resulting solution is 2. 53. Calculate the ka for the acid. Enough of a monoprotic acid is dissolved in water to produce a 0. 0192 m solution.
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